Guys help me on this one!
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prakhargupta3301:
how*
Can you pls give sol
U Like sample paper...??
no real CBSE board exam papers. not sample
I can give you the solution. but only of first part.
I can't explain why it's a double answer ok?
Yes pls give me
wait
But how would you give....?
just wait i will
Answers
Answered by
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common difference =19 1/3 -20=(3*19+1)/3 -20
=57/3 -20 =19-20=-1
300=(n/2)(40+(n-1)(-1))
solve for n
=57/3 -20 =19-20=-1
300=(n/2)(40+(n-1)(-1))
solve for n
Answered by
0
hiii,
The Difference =19 1/3-20
=(3*19+1)/3-20
= 57 / 3 -20
= 19 - 20
= -1
300 = ( n / 2 )
(40+ ( n-1) (-1))
hope help
plz mark my answer as a brainliest answer
The Difference =19 1/3-20
=(3*19+1)/3-20
= 57 / 3 -20
= 19 - 20
= -1
300 = ( n / 2 )
(40+ ( n-1) (-1))
hope help
plz mark my answer as a brainliest answer
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