Question

guys help me out ...its urgent solve x$\frac{x}{x-1} +\frac{x-1}{x} =4$ $x\neq 1$ $x\neq 4$

Answer 1

Answer:

${\frac{1+\sqrt3}{2} }$ or $\frac{1-\sqrt{3} }{2}$

Step-by-step explanation:

given that ,

$\frac{x*x}{x-1*x\\}$+$\frac{(x-1)*(x-1)}{x*(x-1)}$ = 4

therefore 4 * (x-1)*x = x*x+(x-1)^2

4x^2 - 4x = x^2 + x^2 +1 - 2x

2x^2 = 1 + 2x

2x^2 - 2x - 1 = 0

therefore x = ${\frac{1+\sqrt3}{2} }$ or $\frac{1-\sqrt{3} }{2}$