Chemistry, asked by sudipta10, 1 year ago

guys help me to solve the problem no. 62

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Answered by Anonymous

the molecular mass of 2KCLO3=2(39+35.5*3)=2(39+106.5)=2*145.5g=291g

the molecular mass of the 302=3*16*2=96g

therefore

12.25g of KCLO3 will form =96/291*12.25=4.04 g of o2

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