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Length of cuboid = 15 cm
Breadth of cuboid = 10 cm
Height of cuboid = 5 cm
(1)
Surface Area of cuboid = 2(lb + bh + lh)
=> 2(15 * 10 + 10 * 5 + 15 * 5)
=> 2(150 + 50 + 75)
=> 550
(2)
Curved Surface Area of cylinder = 2πrh
=> 2 * (22/7) * 3.5 * 5
=> 110
Thus,
Surface Area of remaining block = 550 + 110 - 2 * (2πr²)
=> 550 + 110 - 2 * (2 * 22/7 * 3.5²)
=> 550 + 110 - 2 * (38.5)
=> 660 - 77
=> 583 cm^2
Hence, Surface area of remaining block = 583 cm².
#BeBrainly
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