Question

guys help me to solve this question as soon as possible please ​

Answer 1

Can you tell which book is this

Answer 2

Length of cuboid = 15 cm

Breadth of cuboid = 10 cm

Height of cuboid = 5 cm

(1)

Surface Area of cuboid = 2(lb + bh + lh)

=> 2(15 * 10 + 10 * 5 + 15 * 5)

=> 2(150 + 50 + 75)

=> 550

(2)

Curved Surface Area of cylinder = 2πrh

=> 2 * (22/7) * 3.5 * 5

=> 110

Thus,

Surface Area of remaining block = 550 + 110 - 2 * (2πr²)

=> 550 + 110 - 2 * (2 * 22/7 * 3.5²)

=> 550 + 110 - 2 * (38.5)

=>  660 - 77

=> 583 cm^2

Hence, Surface area of remaining block = 583 cm².

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