guys help me with this sum
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Step-by-step explanation:
OE is perpendicular on the chord AB .
(by theorem - perpendicular line from the centre bisects the chord)
AE = EB
In triangle ACE and triangle CEB ,
AE = EB
CE = EC (common)
<AEC = <CEB (both 90° each)
By SAS C.R. , triangle ACE is congruent to triangle CEB .
AC = CB (by CPCT)
Hence ,ABC is an isosceles triangle as its two sides are equal..
hope it helps !
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