Math, asked by himanshi11621, 9 months ago

Guys help yrr kal paper hai final 9th ka maths ka...plzzz help​

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Answered by DevanshVats
2

Answer:

 \frac{7 +  \sqrt{5} }{7 -  \sqrt{5} }  -  \frac{7 -  \sqrt{5} }{7 +  \sqrt{5} }   \\  taking \: lcm \\  \frac{  {(7 +  \sqrt{5 } )}^{2}  - ( {7 -  \sqrt{5}) }^{2} }{(7 -  \sqrt{5})(7 +  \sqrt{5} ) }  \\   \frac{ {7}^{2}  +  { (\sqrt{5}) }^{2}  + 14 \sqrt{5} -  {7}^{2} -  { (\sqrt{5} )}^{2}   + 14 \sqrt{5}  }{ {7}^{2}  -  { (\sqrt{5} )}^{2} }  \\  \frac{28 \sqrt{5}}{44}  \\  \frac{7 \sqrt{5} }{11 }  = a +  \frac{7 \sqrt{5} b}{11}  \\ on \: comparing \\ a = 0 \: and \: b = 1

Here is solution.....

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