guys I am not understanding anything in this sum
it is of probability sum of class 10
tomorrow in evening I have exam of this chapter
pls help me to understand this sum in easier way
pls
pls
pls
pls
Answers
Answer:
don't worry when Soham bhaiiya is there for maths
pls mark my answer as brainliest pls
Step-by-step explanation:
so basically leap year has 366 days in total instead of ordinary year which consists of 365 days
so we know that 1 week=7 days
hence 366 days=366/7 weeks ie 52 weeks+2 days as 366 can't get divided completely
so now these 2 days are nothing but 2 possible odd days in 366 days
so as there are 52 weeks we can conclude that there must be 52 thursdays in it
so but we just need to focus and should give emphasis on these 2 extra ie 2 odd days
so 2 odd days can be any day our of 7 days
so let us now consider sample space be S
so S={(Sun,Mon),(Mon,Tue),(Tue,Wed),
(Wed,Thurs),(Thurs,Fri),(Fri,Sat)
(Sat,Sun)}
so hence n(S)=7
now let A be the event so as to just get thursdays in any of two pairs
So A={(Wed,Thurs),(Thurs,Fri)}
n(A)=2
so now using
P(A)=n(A)/n(S)
=2/7
hence probability of getting 53 thursdays in leap year is 2/7