Question

Guys I have another simultaneous equation pls help me with this too​

Answer 1

Step-by-step explanation:

in the above picture there is my answer u can refer my answer and if it is useful then only u can mark me as brainliest...... .

Answer 2

ANSWER

$\frac{x}{6} + \frac{y}{15} = 4.........eq(1) \\ \\ \frac{x}{3} - \frac{y}{12} = \frac{19}{4} ............eq(2) \\ \\ multiply \: eq(1) \: by \: - 2 \\ \\ \frac{ - x}{3} - \frac{2y}{15} = - 8........eq(3) \\ \\ add \: eq(3) \: and \: eq(2) \\ \\ \frac{x}{3} - \frac{x}{3} - \frac{2y}{15} - \frac{y}{12} = \frac{19}{4} - 8 \\ \\ - y( \frac{2}{15} + \frac{1}{12} ) = \frac{ - 11}{4} \\ \\ y( \frac{ 8+5 }{60} ) = \frac{11}{4} \\ \\ y( \frac{13}{15} ) = 11 \\ \\ y = \frac{165}{13} .....put \: in \: eq(3) \\ \\ \frac{ - x}{3} - \frac{ 2 \frac{165}{13} }{15} = - 8 \\ \\ - \frac{x}{3} - \frac{2 \times 165}{13 \times 15} = - 8 \\ \\ - \frac{x}{3} - \frac{22}{13} = - 8 \\ \\ \frac{ - x}{3} = - 8 + \frac{22}{13} \\ \\ - \frac{x}{3} = \frac{ - 104 + 22}{13} \\ \\ - x = 3( \frac{ - 82}{13} ) \\ \\ x = \frac{246}{13}$