guys i need answer fast
k(k+1)(2k+1)+6(k+1)^2÷ 6
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Answer:
2k³+4k²+3k+1.
Step-by-step explanation:
= (k²+k)(2k+1)+{6(k+1)²}/6
= 2k³+k²+2k²+k+k²+1+2k
= 2k³+4k²+3k+1
=2k²(k+2)+3k+1
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