Question

Guys i need answer for these questions​

Answer 1

Answer:

discriminant :- -(31)

roots are not real number

Step-by-step explanation:

let a bi-quadratic equation be (ax^2 + bx +c) .

1. discriminant equals to b^2 - 4ac
2. if b^2 - 4ac < 0 then roots are not real number.

here in this equation b= 1, a= 2, c=4

so b^2 - 4ac = (1)^2 - 4×2×4 = 1 - 32 = -(31)

hope it helps....

plz make it brainliest answer..