Question

GUYS I NEED YOUR HELP PLEASE TO SOLVE THIS SEQUENCE
1+2-3+4+5-6+...+(3n-1)-3n

Answer 1

Answer:

Given: (2n−1),(3n+2) and (6n−1) are in AP.

So, difference between two consecutive terms is same.

So, (3n+2)−(2n−1)=(6n−1)−(3n+2)

(3n+2)+(3n+2)=6n−1+2n−1

6n+4=8n−2

8n−6n=4+2

or n=3

Numbers are:

2×3−1=5

3×3+2=11

6×3−1=17

Answer: (5,11,17) are required numbers.

Step-by-step explanation:

here yur answer