Guys I need your help.
Those who will answer me I will mark him/her the brainliest. Promise.
Find the adverbs and adverbial phrases in the passage and write
them.
Everyone is waiting eagerly for the new basketball court to be ready. Last Friday
workmen laid the new surface. They worked hard all day and managed to complete the
task before nightfall. The opening ceremony will take place next Saturday. Students
have been waiting patiently for a long time for a new court to be constructed. They all
cheered enthusiastically when the principal announced the news to them at the
assembly. When the court is in use, students will feel the benefit immediately. It will be
used for basketball practice every day and matches will be organsied against other
schools most weeks. It is hoped that the new court will make students take the game
more seriously.
Answers
Given:
Length of Rectangle = 40 cm
Breadth of rectangle = 10 cm
\sf Area_{\;(square)} = Area_{\;(rectangle)}Area
(square)
=Area
(rectangle)
⠀⠀
To find:
Perimeter of square?
⠀⠀━━━━━━━━━━━━━━━━━━━━━
☯ Let side of square be x cm.
⠀⠀⠀
\begin{gathered}\underline{\bigstar\:\boldsymbol{According\:to\:the\:question\::}}\\ \\\end{gathered}
★Accordingtothequestion:
\sf Area_{\;(square)} = Area_{\;(rectangle)}Area
(square)
=Area
(rectangle)
⠀⠀
We know that,
⠀⠀
\sf Area_{\;(square)} = (side)^2Area
(square)
=(side)
2
\sf Area_{\;(Rectangle)} = length \times breadthArea
(Rectangle)
=length×breadth
⠀⠀
Therefore,
⠀⠀
\begin{gathered}:\implies\sf side \times side = length \times breadth\\ \\\end{gathered}
:⟹side×side=length×breadth
\begin{gathered}:\implies\sf x \times x = 40 \times 10\\ \\\end{gathered}
:⟹x×x=40×10
\begin{gathered}:\implies\sf x^2 = 400\\ \\\end{gathered}
:⟹x
2
=400
\begin{gathered}:\implies\sf \sqrt{x^2} = \sqrt{400}\qquad\quad\bigg\lgroup\bf Squaring\;both\;sides \bigg\rgroup\\ \\\end{gathered}
:⟹
x
2
=
400
⎩
⎪
⎪
⎪
⎧
Squaringbothsides
⎭
⎪
⎪
⎪
⎫
\begin{gathered}:\implies{\underline{\boxed{\frak{\purple{x = 20}}}}}\;\bigstar\\ \\\end{gathered}
:⟹
x=20
★
\therefore\;{\underline{\sf{Side\;of\;square\;is\;{\textsf{\textbf{20\;cm}}}.}}}∴
Sideofsquareis20cm.
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Now, Finding Perimeter of square,
⠀⠀
\begin{gathered}\dag\;{\underline{\frak{As\;we\;know\;that,}}}\\ \\\end{gathered}
†
Asweknowthat,
\begin{gathered}\star\;{\boxed{\sf{\pink{Perimeter_{\;(square)} = 4 \times side}}}}\\ \\\end{gathered}
⋆
Perimeter
(square)
=4×side
\begin{gathered}:\implies\sf Perimeter_{\;(square)} = 4 \times 20\\ \\\end{gathered}
:⟹Perimeter
(square)
=4×20
\begin{gathered}:\implies{\underline{\boxed{\frak{\purple{Perimeter_{\;(square)} = 80\;cm}}}}}\;\bigstar\\ \\\end{gathered}
:⟹
Perimeter
(square)
=80cm
★
\therefore\;{\underline{\sf{Perimeter\;of\;square\;is\;{\textsf{\textbf{80\;cm}}}.}}}∴
Perimeterofsquareis80cm.
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\begin{gathered}\qquad\qquad\boxed{\underline{\underline{\pink{\bigstar \: \bf\:Formulas\:related\:to\:it\:\bigstar}}}} \\ \\\end{gathered}
★Formulasrelatedtoit★
\begin{gathered}\begin{array}{|c|c|c|}\cline{1-3}\bf Shape&\bf Area\ formula&\bf Perimeter\ formula\\\cline{1-3}\sf Square&\tt side \times side}&\tt 4 \times side\\\cline{1-3}\sf Rectangle&\tt length \times breadth&\tt 2(length + breadth)\\\cline{1-3}\sf Triangle&\tt \dfrac{1}{2} \times base \times height&\tt sum\of\ all\ sides\ of\ \triangle\\\cline{1-3}\end{array}\end{gathered}