Guys I want your help in solving maths please will you help me ... The Count of bacteria in a culture was initially 5,25,000. If it is increasing at the rate of 3 1 /2 % per hour, find the count of bacteria at the end of 2 hours.
Answers
Answer:
According to teh question,
r1 = rate of interest for the first hour = 10%, r2 = rate of interest for the second year = -8%, r3 = rate of interest for the third hour = 12%
The count of bacteria in the sample is 13125000.
The count of bacteria after 3 hours = 1312500 × (1 + 10/100)(1 - 8/100)(1+12/100)
= 1312500 × 1.1 × 0.92 × 1.12
= 1487640
Answer:
5985000
Step-by-step explanation:
No. of bacteria = 525000
the \: percentage \: at \: which \: it \: changes \: per \: hour \: =thepercentageatwhichitchangesperhour=
\frac{7}{2}\% \: per \: hour
2
7
%perhour
now ,
therefore,
no. of bacteria increasing per hour = 7/2% of 525000 = 525000/100×7/2 = 36,750 bacterias per hour ..
now ,
in 2hrs it will increase = 2×36,750 = 73,500 bacterias .
now ,
at the end of 2hrs the no. of bacteria = 73500+525000 => 5985000
hope it helps !!!
All the best !!