Question

guys it's urgent please help and explain please that how you did it​

Answer 1

No sorry.brother I'm very very sorry

Answer 2

$\huge\boxed{Answer}$

Perimeter of rhombus = 20 cm

4 × each side = 20 cm

each side = 5 cm

let the two diagonals of this Rhombus

are AC & BD which intersect on O .

Given , one diagonal (AC) = 6 cm

then , AO = OC = 3 cm

In ∆ AOB ,

AB² = AO² + OB²

5² = 3² + OB²

OB² = 5² - 3²

OB² = 4²

OB = 4 cm

OD = OB = 4 cm

then , Diagonal (BD) = OB + OD = 8 m

Now ,

Area of Rhombus = 1/2 × product of diagonals

= 1/2 × AC × BD

= 1/2 × 6 × 8

= 3 × 8

= 24 cm²