Question

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Answer 1

$\sqrt{112} -\sqrt{63} + \dfrac{224}{\sqrt{28} }$

Rewrite them in their simplest form:

$= \sqrt{7 \times 16} -\sqrt{9 \times 7} + \dfrac{224}{\sqrt{4 \times 7} }$

$= 4\sqrt{7} - 3\sqrt{7} + \dfrac{224}{2\sqrt{ 7} }$

Put them into a single fraction:

$= \dfrac{4\sqrt{7} (2\sqrt{7}) }{2\sqrt{7} } - \dfrac{3\sqrt{7} (2\sqrt{7})}{2\sqrt{7}} + \dfrac{224}{2\sqrt{ 7} }$

$= \dfrac{8(7) }{2\sqrt{7} } - \dfrac{6(7)}{2\sqrt{7}} + \dfrac{224}{2\sqrt{ 7} }$

$= \dfrac{8(7) - 6(7) + 224 }{2\sqrt{7} }$

Simplify again:

$= \dfrac{56 - 42+ 224 }{2\sqrt{7} }$

$= \dfrac{238}{2\sqrt{7} }$

$= \dfrac{119}{\sqrt{7} }$

Remove the denominator:

$= \dfrac{17 \times 7}{\sqrt{7} }$

$= \dfrac{17 \times \sqrt{7} \times \sqrt{7} }{\sqrt{7} }$

$= 17\sqrt{7}$

Answer: 17√7

Answer 2

Answer:

17√7 is the answers for this question

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