Math, asked by blasterblade2017, 10 months ago

guys listen i asked this question earlier no one answered
now i m again asking it only those who know it answer it and faster because its urgent.
The points a(4,-2) b(7,2) c(0,9) and d(-3,5) forma parallelogram. Find the length of the altitude of the parallelogram on the base ab.
Again i m saying ace,expert or genius or others who know it answer


blasterblade2017: i did nt got the question u asked

Answers

Answered by Anonymous
4
Here let's find equation of two parallel lines AB and CD

and then apply distance formula between parallel lines


A( 4,-2) B( 7,2)

y - ( -2) = ( 2 -(-2))/ 7-4 .( x -4)

y + 2 = 4/ 3 ( x -4)

3y + 6 = 4x -16

3y -4x = -22

3y -4x +22 = 0



C( 0,9) D( -3,5)

Y - 9 = ( 5 -9)/ -3 . x

y - 9 = 4/3 . x

3y -27 -4x = 0


Now distance between 3y -4x +22 = 0

and 3y - 4x -27 = 0

d= 22 -(-27) )/ √3^2 + 4^2


= 49/ √9+16 = 49/√25 = 49/5

blasterblade2017: thanks
blasterblade2017: dhruv bhai
IshitaJaiswal: 49/5 = 9.8cm.
IshitaJaiswal: aapko likhna chahiye thaa...
Answered by Arjunaksd
1

if it help you

plz mark as brainlist

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blasterblade2017: keep it up
Arjunaksd: thnkx bro for brainlist
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