Math, asked by prasadmunna940720785, 8 months ago

guys only solve 6th question

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Answered by Glorious31
0

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༒︎Case 1

q(y) = 3y {}^{4}  - 5y {}^{3}  +  {y}^{2}  + 8 \\  \\  \\ q( - 1) = 3( - 1) {}^{4}  - 5( - 1) {}^{3}  + ( - 1) {}^{2}  + 8 \\  = 3  + 5 + 1 + 8 \\  = 17

༒︎Case 2

q(2) = 3(2) {}^{4}  - 5(2) {}^{3}  + (2) {}^{2} + 8 \\  \\  \\  = 24 - 40 + 4 + 8 \\  \\  =  - 4

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@ Lalitya ⚔️


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