guys please ans this questions
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In ques5.
angleC=angleAED
angleAED=120°(corresponding angles)
in ∆AED,
angle AED+angle D + angleA=180°(angle sum property)
angleA=25°
in ∆ABC,
angleA + angleB + angleC=180°
angleB=35°
Hence, angleABC=35° ,angleBAC=25° ,angleAED=120°
angleC=angleAED
angleAED=120°(corresponding angles)
in ∆AED,
angle AED+angle D + angleA=180°(angle sum property)
angleA=25°
in ∆ABC,
angleA + angleB + angleC=180°
angleB=35°
Hence, angleABC=35° ,angleBAC=25° ,angleAED=120°
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