Question

guys please ans this questions

Answer 1

In ques5.
angleC=angleAED
angleAED=120°(corresponding angles)
in ∆AED,
angle AED+angle D + angleA=180°(angle sum property)
angleA=25°
in ∆ABC,
angleA + angleB + angleC=180°
angleB=35°

Hence, angleABC=35° ,angleBAC=25° ,angleAED=120°