Question

guys please answer I am having exam

Answer 1

Answer:

Step-by-step explanation:

In ∆ACP,

Using Pythagoras theorem,

H²=P²+B²

Hence, AP²=AC²+CP²

CP²=AP²-AC²

CP²=(15)²-(12)²

CP²=225-144

CP=√81

CP=9

Similarly, in ∆BPD

BP²=BD²+PD²

PD²=BP²-BD²

PD=√15²-9²

PD=√225-81

PD=√144

PD=12

Now, CD=PD+CP

CD=12+9

CD=21

Answer 2

from Pythagoras theorem
in triangle ACP
angle Ap square=ACsquare+cpsquare
15square=12square+cpsquare
cp=squarerootof225-144
cp=9
lly
pD=square root of225-81
pD=12
cD=cp+pD
cD=12+9
cD=21