Guys please answer it, it's quite urgent
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1
1.5 V.
The equivalent resistance is 6 ohms.
The current is given as 1 A, so the total drop across each parallel branch will be 6 V.
Now the drop in (5 ohms + 15 ohms) is 6 V.
These are in series - same current - so, drop across 5 ohms would be (5 / 5 + 15) * 6 V = 6 / 4 V = 1.5 V.
Answered by
0
Requ = 5 + 15 = 20 ohm
and all resistance are parllel
so,
1/Rp = 1/R1 + 1/R2 + 1/R3
= 1/10 + 1/20 + 1/60
= 10/60 = 1/6
Rp = 6ohm
according to ohm,s law
V = IR
V = 1*6 = 6v
for resistance 5 ohm,
according to ohm's law
V = IR
= 1* 5 = 5v
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