guys please answer question number 13 it is urgent
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shifting the values to get the standard equation of a straight line we get
this is similar to
to transform this equation into y=mx +c
we need to move the terms around a bit
the way to transfor standard equation in y=mx+c is
Ax +By+C=0
By= -Ax -C
y= -Ax/B -C/B
where m =-A/B and c =-C/B
using this method in 13x-12y -25=0 we get
y=-13x/12 + 25/12
where m = -13x/12
and c = 25/12
nidhi411:
but we need to find m and c
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Given Equation is 13x - 12y = 25.
We have to transpose the terms to get the y value.
-12y = -13x + 25
Hence the given equation is in the slope-intercept form y = mx + c
m = 13/12 and c = -25/12
On substituting the values of x = 1 and y = 1.
We get
13x - 12y = 25
13(1) - 12(1) = 25
1 = 25
Hence They are not the solutions of the equation
Hope this helps!.
We have to transpose the terms to get the y value.
-12y = -13x + 25
Hence the given equation is in the slope-intercept form y = mx + c
m = 13/12 and c = -25/12
On substituting the values of x = 1 and y = 1.
We get
13x - 12y = 25
13(1) - 12(1) = 25
1 = 25
Hence They are not the solutions of the equation
Hope this helps!.
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