Math, asked by gchowdhary15, 10 months ago

Guys, please answer this question.​

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Answered by Anonymous
1

Answer:

Answer = 1

...

2( \frac{ \cos(90 - 32) }{ \sin(32) } ) -  \sqrt{3} ( \frac{ \cos(38) }{ \sin(52) }  \div  \tan(15)  \times  \sqrt{3}  \times  \tan(90 - 15)

2( \frac{ \sin(32) }{ \sin(32) } ) -  \sqrt{3}  \times  \frac{1}{ \sqrt{3} }

2 - 1 = 1

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