Question

Guys please answer this question.I am greatly in need of it as it is graded.I'll have to submit this by tomorrow morning.Pl Pl help me.

Answer 1

Answer:

1. 1.5 m/s²

2. 2.5 m/s²

3. 120 m

Explanation:

Acceleration is given by

$a={dv\over dt}$  i.e., slope of the given graph

Since, velocity is increasing till 10 seconds, the body is in acceleration. And in next 6 seconds, it is decelerating because velocity is decreasing.

So, for time interval between t = 0 to t = 10 sec.,

Acceleration, $a={dv\over dt}={15\over10}=1.5\,\,m/s^2$

And, for time interval between t = 10 to t = 16 sec.,

Deceleration = ${15\over6}=2.5\,\,m/s^2$

Distance covered by body is given by

$s=v\times dt$ i.e., area of the graph

So, Distance covered will simply be

$({1\over2}\times15\times10)+({1\over2}\times15\times6)=120\,\,metres$