Question

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Answer 1

Answer:

2X-EA-IP=0

Explanation:

lectron affinity: The amount of energy released when an electron is added to the outermost shell of one mole of an isolated gaseous atom in its lower energy state.

Ionisation energy: Minimum energy required to remove most loosly held outer most shell e – in ground state from an isolated gaseous atom is known as ionisation potential.

X=IP+EA/2

2X-IP-EA=0

Answer 2

I.P = ionisation potential -The energy required to remove an e-. from the outer most shell

E.A. = is the energy released when an e- is added in the outermost shell

E.N. = is the tendancy of an atom to attract a shared pair of e-

1) Mullikan's scale. 2) pouling scale

X = EI.+EA. X= EI+EA

2. 540

= EI and EA ev.

2x = IP + EA

2x -IP -EA=0 .........ans.

so, the option 1 is correct answer dear.

I hope you understand...

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