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Question :
A wheel has a constant angular acceleration of 2 rad/s², During a certain 4s interval, it turns through an angle of 72 rad. Assuming that at t = 0, angular speed ω⁰ = 6 rad/s how long, is motion at the start of this 4 s interval?
A) 7 sec
B) 9 sec
C) 4 sec
D) 10 sec
Answer :
★ First case :
- α = 2 rad/s²
- t = 4s
- θ = 72 rad
First we need to find initial angular velocity of wheel
Using second equation of rotational kinematics,
➝ θ = ωt + 1/2 αt²
➝ 72 = 4ω + 1/2 (2)(4)²
➝ 72 = 4ω + 16
➝ 4ω = 56
➝ ω = 14 rad/s
★ Second case :
- ω⁰ = 6 rad/s
- ω = 14 rad/s
- α = 2 rad/s²
In this case we have asked to find time.
Using first equation of rotational kinematics,
➝ ω = ω⁰ + αt
➝ 14 = 6 + 2t
➝ 8 = 2t
➝ t = 4 s
∴ (C) is the correct answer!
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