Question

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Answer 1

Question :

Two stones of masses m and 2m are whirled in horizontal circles, the heavier one in a radius r/2 and the lighter one in radius r. The tangential speed of lighter stone is m times that of the value of heavier stone. when they experience same centripetal forces. The value of n is :

Answer :

Given, that two stones of masses m and 2m are whirled in horizontal circles, the heavier one in a radius r/2 and lighter one in radius r$.$

As, lighter stone is n times that of the value of heavier stone when they experience same centripetal forces, we get

$:\implies\tt\:(F_c)_{heavier}=(F_c)_{lighter}$

$:\implies\tt\:\dfrac{2m(v)^2}{(\frac{r}{2})}=\dfrac{m(nv)^2}{r}$

$:\implies\tt\:n^2=4$

$:\implies\:\underline{\boxed{\bf{\purple{n=2}}}}$

∴ (2) is the correct answer!

★ Centripetal force is not a new kind of force. The material forces such as tension, gravitational force, electrical force, friction, etc., may act as the centripetal force in an circular motion.

• Centripetal force is the same given to any force that provides radial inward acceleration to a body in circular motion.

Answer 2

Explanation:

2 answer is correct

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