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Step-by-step explanation
2.Given equal sides is 14 cm
Perimeter of the triangle is 40
We know Perimeter of the triangle is a+b+c
We know that two sides are 14
14+14+c =40. (C=another side)
28+c=40
C=40-28
C=12
The three sides of isosceles triangle is 14;14&12
The area of isosceles triangle is b(h)/2
(b=14&h=12)
14(12)/2
168/2
84
the area of isosceles triangle is 84
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Answer: perimeter =40
Each side =14
Third side =x
Perimeter of ∆= sum of all side
14 +14 +x=40
X =40-28
X=18
Area using herons formulae
S= 14+14+18/2
S= 20
√20(20-14) (20-14) (20-18)
√20 × 16×16×2
√2×10×16×16×2
16×2√10
32√10
Area = 101 . 192or 32√10
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