Question

GUYS PLEASE HELP
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Answer 1

$\mathbb{\huge{\bold{\red{Your\: Solution}}}}$

See the attachment file

diameter of circular pond =40
radius of pond = 20m
depth = 7 = 0.07
Thickness = 2

$\underline\bold{Thickness\:(t)\:= R-r }$

2= R-r
2=R-7
R=2-7
R= 9
π (9^2-7^2)×0.07
π(32)×0.07
2.24πm^2

$<b>$

Thanks ..
$\mathbb{\blue{\huge{NICE \: QUESTION}}}$