Guys please help if tan theta1,tan theta 2, tan theta 3 , tan theta 4 are the roots of x^4+px^3+qx^2+rx+s=0 show that tan(theta 1+theta2+thera 3+theta 4)=r-p/1-q+s.
Answers
Answered by
1
Answer:
From the given equation we get
S
1
=tanθ
1
+tanθ
2
+tanθ
3
+tanθ
4
=sin2β
S
2
=∑tanθ
1
tanθ
2
=cos2β
S
3
=∑tanθ
1
tanθ
2
tanθ
3
=cosβ
and S
4
=tanθ
1
tanθ
2
tanθ
3
tanθ
4
=−sinβ
Now tan(θ
1
+θ
2
+θ
3
+θ
4
)=
1−S
2
+S
4
S
1
−S
3
.
=
1−cos
2
β−sinβ
sin2β−cosβ
=
sinβ(2sinβ−1)
cosβ(2sinβ−1)
=cotβ.
Similar questions