Question

Guys please help its a really emergencyyyy Pls solve it quickly on ur copy​

Answer 1

Step-by-step explanation:

From given statement: 

 

In △ADC

EO∣∣AB∣∣DC

 

By thales theorem: EDAE=OCAO    ...(1) 

 

In △DAB

EO∣∣AB 

 

So, By thales theorem: EADE=OBDO    ...(2) 

 

From (1) and (2) 

 

OCAO=OBDO 

 

(2x+1)(5x−7)=(7x+1)(7x−5) 

 

(5x−7)(7x+1)=(7x−5)(2x+1)

 

35x2+5x–49x–7=14x2–10x+7x−5

 

35x2−14x2–44x+3x−7+5=0

 

21x2−42x+x−2=0

 

21(x−2)+(x−2)=0

(21x+1)(x−2)=0

 

Either (21