Question

guys please help me​

Answer 1

Hi there!

Answer :-

AD and BC are opposite sides of parallelogram ABCD. So,

$\sf\red{AD = BC}$

DE and CF are opposite sides of parallelogram DCFE. So,

$\sf\blue{DE = CF}$

AE and BF are opposite sides of parallelogram ABFE. So,

$\sf\pink{AE = BF}$

So by SSS congruency rule,

Δ ADE ≈ Δ BCF

Now by congruent part of corresponding triangles,

ar(ADE) = ar(BCF)

Hence Proved.