Question

guys please help me...​

Answer 1

Answer:

y= (-9)

Step-by-step explanation:

$\frac{y + 9}{2} = \frac{y - 3}{4}- \frac{y}{3}$

${y + 9} =2( \frac{y - 3}{4}- \frac{y}{3})$

${y + 9} = \frac{y - 3}{2}- \frac{2y}{3}$

${y + 9} = \frac{3y - 9}{6}- \frac{4y}{6}$

${y + 9} = }\frac{-y-9}{6}$

$6y + 54 = -y - 9$

$7y = -63$

$y = -9$

Answer 2

Given Question :-

Solve for y :

$\rm :\longmapsto\:\dfrac{y + 9}{2} = \dfrac{y - 3}{4} - \dfrac{y}{3}$

$\red{\large\underline{\sf{Solution-}}}$

Given equation is

$\rm :\longmapsto\:\dfrac{y + 9}{2} = \dfrac{y - 3}{4} - \dfrac{y}{3}$

On taking LCM of 4 and 3 on RHS, we get

$\rm :\longmapsto\:\dfrac{y + 9}{2} = \dfrac{3(y - 3) - 4y}{12}$

$\rm :\longmapsto\:\dfrac{y + 9}{2} = \dfrac{3y - 9 - 4y}{12}$

$\rm :\longmapsto\:\dfrac{y + 9}{2} = \dfrac{ - 9 - y}{12}$

On multiply by 12 on both sides, we get

$\rm :\longmapsto\:6(y + 9) = - y - 9$

$\rm :\longmapsto\:6y + 54 = - y - 9$

$\rm :\longmapsto\:6y +y = - 54 - 9$

$\rm :\longmapsto\:7y = -63$

$\rm :\longmapsto\:y = - \dfrac{63}{7}$

$\purple{\bf\implies \:\boxed{ \tt{ \: y \: = \: - \: 9 \: \: }}}$

Verification :-

Given equation is

$\rm :\longmapsto\:\dfrac{y + 9}{2} = \dfrac{y - 3}{4} - \dfrac{y}{3}$

Consider LHS

$\rm :\longmapsto\:\dfrac{y + 9}{2}$

On substituting y = - 9, we get

$\rm \: = \:\dfrac{ - 9 + 9}{2}$

$\rm \: = \:\dfrac{0}{2}$

$\rm \: = \:0$

Now, Consider RHS

$\rm :\longmapsto\: \dfrac{y - 3}{4} - \dfrac{y}{3}$

On substituting y = - 9, we get

$\rm \: = \: \dfrac{ - 9 - 3}{4} - \dfrac{ - 9}{3}$

$\rm \: = \: \dfrac{ - 12}{4} - ( - 3)$

$\rm \: = \: - 3 + 3$

$\rm \: = \:0$

So,

$\bf\implies \:LHS = RHS$

Hence, Verified