Question

guys please help me......

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Answer 1

Answer:

Let inner radius be 'r'.

Inner circumference = 176 m

$2\pi \: r = 176 \\ 2 \times \frac{22}{7} \times r = 176 \\ r = 28 \: m$

Now, width = 7 m

So radius of outer circle, R = 28 + 7 = 35 m

So, outer Circumference =

$2\pi \: R = 2 \times \frac{22}{7} \times 35 = 220 \: m$

So, Cost of fencing the outer boundary wall = 220 × 21 = ₹ 4620