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Answers
Distance of the ship from the light house is 51.9m
Let AB=90m represents the hight of lighthouse. point C represents the position of the ship.
Draw ray AM ll Seg BC
angle ACB is the angle of depression
angle MAC = 60°
Also, angle ACB not equal to angle MAC (Alernate angles)
angle ACB = 60°
Let the distance of ship from the lighthouse be x metres
In right angled triangle ABC, to 60°=90/x
= x = 90/square root of 3
= x = 90/square root of 3 × square root of 3
= 90 square root of 3 divided by 3
=30 square root of 3
=30 × 1.73 = 51.9
therefore, distance of the ship from the lighthouse is 51.9m
Answer:
Distance of the ship from the light house is 51.9m
Let AB=90m represents the hight of lighthouse. point C represents the position of the ship.
Draw ray AM ll Seg BC
angle ACB is the angle of depression
angle MAC = 60°
Also, angle ACB not equal to angle MAC (Alernate angles)
angle ACB = 60°
Let the distance of ship from the lighthouse be x metres
In right angled triangle ABC, to 60°=90/x
= x = 90/square root of 3
= x = 90/square root of 3 × square root of 3
= 90 square root of 3 divided by 3
=30 square root of 3
=30 × 1.73 = 51.9
therefore, distance of the ship from the lighthouse is 51.9m
Step-by-step explanation: