Math, asked by sanskriti746, 8 months ago

guys please help me in this question ​

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Answered by neetutagra
1

Answer:

{(2^m)^(m-1/m)}^1/(m+1)

{(2^m)^(m*m-1/m)}^1/(m+1)

{(2^m)^(m^2-1)/m}^1/(m+1). ((a^b)^c=a^b*c)

{(2)^(m*(m^2-1)/m}^1/(m+1)

{2^(m^2-1)}^1/(m+1)

2^{(m^2-1)*1/(m+1)}. ( m^2-1^2=(m+1)(m-1))

2^{(m+1)(m-1)}/(m+1). ( m+1 will cancel out)

2^(m-1)

hope this helps you。◕‿◕。

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