Question

guys please help me to solve this

Answer 1

Your answer follows below

Thank u

Hope this helps you

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@spyder

Answer 2

your question ---> what is the value of $(729)^{-\frac{1}{3}}$

first of all, we have to do prime factors of 729

prime factors of 729 = 3 × 3 × 3 × 3 × 3 × 3
= (3 × 3) × (3 × 3) × (3 × 3)
= 3² × 3² × 3²
= 9 × 9 × 9
= 9³

hence, 729 = 9³

now, $(729)^{-\frac{1}{3}}=(9^3)^{-\frac{1}{3}}$

we know, $(x^n)^m = x^{mn}$ use it here

so, $(9^3)^{-\frac{1}{3}}=9^{-3\times\frac{1}{3}}=9^{-1}=\frac{1}{9}$