Question

guys please help me with this by providing step by step explanation
I'll mark you the brainliest ​

Answer 1

$\large\text{\underline{Let's begin:-}}$

To find the similarity ratio, we could compare the lengths of the corresponding sides.

In this case, the similarity ratio is $1:3$.

$\large\text{\underline{Solution:-}}$

Since,

$\hookrightarrow \overline{AP}:\overline{XY}=1:3$

Then $\overline{PQ}:\overline{YZ}=1:3$, but it is given that $\overline{YZ}=15\text{ (cm)}$.

$\hookrightarrow \overline{PQ}:15=1:3$

Since the product of extremes and means is equal,

$\hookrightarrow 3\overline{PQ}=15$

$\hookrightarrow \overline{PQ}=5\text{ (cm)}$

$\large\text{\underline{Learn more:-}}$

The ratio of the areas for two triangles whose similarity ratio is $a:b$ is $a^{2}:b^{2}$. So, in this case the ratio of two triangles' area will be $1:9$.

Answer 2

Answer:

$\huge \sf{\underbrace{\underline{Answer: -}}}$

Given :-

• Triangle APQ is similar to triangle XYZ
• AP=2.5cm.
• XY=7.5cm
• YZ=15cm.

Answer :-

• PQ=5cm.

To find :-

• PQ= cm.

Solution :-

• Here refer the given above attachment for better understanding.

Hope it helps you.

$\mathcal\purple{Thank you}$.