guys please help me with this question and whoever will give me the answer I will mark them as brainlist but I don't want any useless answer
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Solid
M=50g
T=150°C
C1=?
Final temperature
0=20°C
Water
m=100g
t=11°C
C2=4.2
Heat lost by liquid- Heat gained by water
MC,(T-0)=mC2 (0-1)
50 C, (150-20) = 100×42/10 (20-11)
50×130 C,=420×9
C1=(420×9)/50×130=0.58Jg-10C-1
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