Question

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Answer 1

Answer:

$s = ut + \frac{1}{2} a {t}^{2}$

using this formula for part one u can find the distance

here intial velocity is 0 because it starts from rest

so new equation becomes

$s = \frac{1}{2} a {t}^{2}$

putting a=25, t= 20 u will get your answer which is 5000 meters

for part 2 use formula

$v = u + at$

here u is intial velocity 4m/s

v is final 5m/s

t=3sec

5 = 4 + a×3

a= 1/3 which is 0.33 meter per second square

hope this helps you