Guys, please solve any of them...
It's a choice...
Come on!!!!!
But solve according to 4m ques.
PLEASE, NEED HELP !!!!
Attachments:
Answers
Answered by
27
Answer:
Y=28,X=37
Step-by-step explanation:
Y=angle SQT(alternate interior angles)
X=angle QSR(alternate interior angles)
QRT+QRS=180
QRS=115
QSR+QRS+SQR=180
QSR=37=X
prashant4584:
nice
Answered by
53
➣ 28. When x - 4 = 0, then x = 4
f(x) = ax³ + 3x² - 3
f(4) = a(4)³ + 3(4)² - 3
p = 64a + 48 - 3
p = 64a + 45
g(x) = 2x³ - 5x + a
g(4) = 2(4)³ - 5(4) + a
q = 128 - 20 + a
q = 108 + a
Now, as given 2p = q
So, 2( 64a + 45 ) = 108 + a
128a + 90 = 108 + a
128a - a = 108 - 90
127a = 18
✪ a = 18/127
➣ 29. ∠QRT = ∠SQR + ∠QSR
65° = 28° + ∠QSR
37° = ∠QSR
Since, PS ⊥ SR
y + 37° = 90°
✪ y = 53°
In ∆PQS, due to angle sum property
y + x + ∠QPS = 180°
53° + x + 90° = 180°
x = 180° - 143°
✪ x = 37°
➣ 30. ✪ Please see the image attatched.
f(x) = ax³ + 3x² - 3
f(4) = a(4)³ + 3(4)² - 3
p = 64a + 48 - 3
p = 64a + 45
g(x) = 2x³ - 5x + a
g(4) = 2(4)³ - 5(4) + a
q = 128 - 20 + a
q = 108 + a
Now, as given 2p = q
So, 2( 64a + 45 ) = 108 + a
128a + 90 = 108 + a
128a - a = 108 - 90
127a = 18
✪ a = 18/127
➣ 29. ∠QRT = ∠SQR + ∠QSR
65° = 28° + ∠QSR
37° = ∠QSR
Since, PS ⊥ SR
y + 37° = 90°
✪ y = 53°
In ∆PQS, due to angle sum property
y + x + ∠QPS = 180°
53° + x + 90° = 180°
x = 180° - 143°
✪ x = 37°
➣ 30. ✪ Please see the image attatched.
Attachments:
Similar questions