guys please solve it
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Hope it helps....!!!
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Solution:
30000 = 100000(0.8)^n
=> 0.3 = 0.8^n
Using logs we get:
log0.3 = n log0.8
=> n = (log0.3)/log0.8 = 5.4 years......assuming the depreciation is annual @ 20%
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#Be Brainly☺️
---------------------------
Solution:
30000 = 100000(0.8)^n
=> 0.3 = 0.8^n
Using logs we get:
log0.3 = n log0.8
=> n = (log0.3)/log0.8 = 5.4 years......assuming the depreciation is annual @ 20%
----------------------------
#Be Brainly☺️
anuj9704:
no no its clear
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