Math, asked by anuj9704, 1 year ago

guys please solve it

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Answered by Anonymous
1
Hope it helps....!!!

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Solution:

30000 = 100000(0.8)^n 

=> 0.3 = 0.8^n 

Using logs we get: 

log0.3 = n log0.8 

=> n = (log0.3)/log0.8 = 5.4 years......assuming the depreciation is annual @ 20% 
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