Question

guys please solve it fast​

Answer 1

Answer:

$You are given that \\ lines l and m intersect each other at A.</p><p></p><p>Let PB is perpendicular on l and</p><p></p><p>PC⊥m. It is given that PB=PC.</p><p></p><p>You need to show \\ that ∠PAB=∠PAC.</p><p></p><p>Let us \\ consider △PAB and △PAC. In \\ these two triangles,</p><p></p><p>PB=PC (Given) \\ </p><p></p><p>∠PBA=∠PCA=90∘ (Given)</p><p></p><p>PA=PA (Common side)</p><p></p><p>So, △PAB≅△PAC (RHS rule)</p><p></p><p>So, ∠PAB=∠PAC(CPCT)</p><p></p><p>$

Step-by-step explanation:

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Answer 2

Hello Dear User !!!

Kindly Refer to attachment