Math, asked by mallickadyasha21, 2 months ago

Guys please solve it quickly please
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Answered by Anonymous
19

Answer:

\mathtt\blue{FORMULA \:  USED:-}

\mathtt{ {a}^{m} \times  {b}^{m}  =  {a}^{m + n} }

\mathtt{ {a}^{m}  \div  {b}^{m}  =  {a}^{m  -  n} }

\mathtt{ {a}^{0}  = 1}

\mathtt\blue{SIMPLIFY:-}

\mathtt{ =  \frac{ ({x}^{a + b)^{2}  }   \times (x^{b + c})^{2}  \times  ({x}^{c + a})^{2} }{ ({x}^{a}  {x}^{b} {x}^{c})^{4}   } }

\mathtt{  =  \frac{  {x}^{2a + 2b}  \times  {x}^{2b + 2c}  \times  {x}^{2c + 2a} }{ {x}^{4a}  {x}^{4b} {x}^{4c}  } }

\mathtt{ =  \frac{ {x}^{2a + 2a + 2b + 2b + 2c + 2c} }{ {x}^{4a + 4b + 4c} } }

\mathtt{ =  \frac{x^{4a + 4b + 4c} }{ {x}^{4a + 4b + 4c} } }

\mathtt{  =  {x}^{4a - 4a + 4b - 4b + 4c - 4c}  }

\mathtt{  = {x}^{0} }

\fbox\blue{ = 1}

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