Question

Guys please solve my question and give the right answer​

Answer 1

Answer:

Hope it helps you please mark brainliest

Answer 2

SOLUTION

Given,

h= 16cm

r1=20cm

r2=8cm

Volume of frustum of the cone

$= > \frac{1}{3} \pi \: h( {r}^{2} 1 + {r}^{2} 2 + r1r2) \\ = > \frac{1}{3} \times 3.14 \times 16( {20}^{2} + {8}^{2} + 20 \times 8) \\ = > 10 .450cm {}^{3}$

Since,

1000cm^3 = 1l

=) 10.450cm^3 = 1/1000× 10.450

=) 10.45l

Cost of 1l of milk = Rs.22

=) cost of 10.45 of milk= Rs.(20× 10.45)

=) 229.9Rs. [Answer]

Hope it helps ☺️