Question

GUYS PLEASE SOLVE THE 4TH SUM. ​

Answer 1

★Question:

a = -2, b = -1 then $a^{-b} - b^{-a} \: =$

★Solution:

by putting the values of a and b

$a^{-b} - b^{-a} = \\ \\ \\ (-2)^{-(-1)} - (-1)^{-(-2)}\\ \\ \\ = (-2)^{1} - (-1)^2\\ \\ \\ = -2 - (1) \\ \\ \\ -2-1 = - 3\\ \\ \\{\pink{\boxed{ a^{-b} - b^{-a} = -3}}}$

★Additional Information :

$Laws\:of\: exponents \\ \\ \\ \implies a^m \times a^n = a^{m+n}\\ \\ \\ \implies \frac{a^m}{a^n} = a^{m-n}\\ \\ \\ \implies (a^m)^n = a^{mn}\\ \\ \\ \implies a^{-m} = \frac{1}{a^m} \\ \\ \\ \implies a^0 = 1$

Answer 2

Question:

$If a = -2 and b = -1 , then find the value of$$a^{-b} - b^{-a}$

To Find:

The value of $a^{-b} - b^{-a}$

Solution:

Putting the value of a and b in the equation , we get;

$(-2)^{-1} - (-1)^{-2}$

$(-2)^{-(-1)} + 1^{-(-2)}$

$-2 - 1$

= -3