guys please solve the 6 questions it's urgent
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⭐hey there!!
Given :- u = 20m/s
=> s = 50 m
Now use 3rd eqn of motion,
=> v² = u² + 2aS
Body comes to rest so v = 0
=> 0 = (20)² + 100a
=> a = - 400/100 = - 4 m/s² ( retardation)
=> mass = 1 kg
Force of friction is opposite to the direction of force
So, f = - ma = -1 × (-4) = 4 N
_______________________________________
⭐hope it will help u
Given :- u = 20m/s
=> s = 50 m
Now use 3rd eqn of motion,
=> v² = u² + 2aS
Body comes to rest so v = 0
=> 0 = (20)² + 100a
=> a = - 400/100 = - 4 m/s² ( retardation)
=> mass = 1 kg
Force of friction is opposite to the direction of force
So, f = - ma = -1 × (-4) = 4 N
_______________________________________
⭐hope it will help u
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