Question

guys please solve this......​

Answer 1

let

the radius of base of CYCLINDER=2x

the hieght of CYCLINDER=3x

given

the volume of CYCLINDER=1617cm³

According to the question

$↪\pi {r}^{2} h = 1617 \\ \\ ↪ \frac{22}{7} \times 2x \times 2x \times 3x = 1617 \\ \\ ↪12 {x}^{3} \times 22 = 1617 \times 7 \\ \\ ↪ {x}^{3} = \frac{1617 \times 7}{12 \times 22} \\ \\ ↪ {x}^{3} = \frac{343}{8} \\ \\ ↪ {x}^{3} = ( \frac{7}{2} ) {}^{3} \\ \\ ↪x = \frac{7}{2} = 3.5$

•radius=2*3.5=7cm

•height=3*3.5=10.5cm

*hence:-

Total surface area of CYCLINDER

↪2πr(r+h)

↪2*22/7*7(7+10.5)

↪2*22*17.5

↪770cm²