Question

Guys please solve this please..please help me...​

Answer 1

it's very easy

first of all find the factors of 10,25,6.

I think you know it.

after taking out the factors, follow the following process.

$\frac{3 {}^{5 } \times (2 \times 5) \times 5 {}^{2} }{5 {}^{7} \times (3 \times 2) {}^{5} }$

$\frac{3 {}^{5} \times 2 \times 5 \times 5 {}^{2} }{5 {}^{7} \times 3 {}^{5} \times 2 {}^{5} }$

now collect same numbers and do subtraction and addition whatever required.

Please mark brainiest and hit a thanks

Answer 2

Answer:

17) 1

18) 3a³b³c³

Step-by-step explanation:

17) (3⁵) × (2×5)⁵ × (5²) ÷ { 5⁷ × (2×3)⁵}

=> ( 3⁵ × 2⁵ × 5⁵×5² ) ÷ (5⁷ × 2⁵ × 3⁵)

=> (3⁵ × 2⁵ × 5⁷ ) ÷ ( 5⁷ ×2⁵×3⁵)

{each term get cancelled}

=> 1

18)

(2/5) a²b × (-15b²ac) × (-1/2c²)

=> { 2×(-15)(-1) ÷ ( 5×2) } a²b ×b²ac ×c²

=> (30/10) a³b³c³

=> 3a³b³c³