Question

guys please solve this question​

Answer 1

Answer:

9 hours

Step-by-step explanation:

The distance travelled by both the cars will be same

Bases on this

let x be the number of hours the cars travelled

First car with uniform velocity 10km/hr

so the distance = velocity *time travelled

d1 = 10n

Second car with non - uniform velocity constant acceleration 0.5 km/hr = 1/2 km/hr

$d2 = 8 + (8 + \frac{1}{2} ) + (8 + \frac{1}{2} + \frac{1}{2} ) + ............. + (8 + \frac{1}{2} + \frac{1}{2} + ........) \\ d2 = 8 + 8 + \frac{1}{2} + 8 + \frac{1}{2} + \frac{1}{2} + ........ + (8 + \frac{1}{2} + \frac{1}{2} + ...... + \frac{n - 1}{2} ) \\ d2 = 8n + \frac{1}{2} (1 + 2 + 3 + ..... + (n - 1)) \\ d2 = 8n + \frac{1}{2} { \frac{(n - 1)n}{2} }$

we know that

d1 = d2

$10n = 8n + \frac{1}{2} \frac{(n - 1)n}{2}$

40n = 32n + n² -n

n² - 9n =0

n(n-9)=0

n = 0 ; n=9

we know that at n=0, at start point both cars met and again at 9 hours they both met

Hope this will be clear, if you've any doubts comment below ;))