Question

guys please solve this question!!! Its really urgent guys!! tomorrow I am having my exams!! please its verry urgent!!!

Answer 1

here is ur answer....

Answer 2

Hello there! :)

Usually I'd rearrange the equation into a form that I'm more familiar with--that is, y=mx+C because m would be the slope of the line and C would be the y-intercept.

So:

3x+4y-7 = 0

4y = -3x + 7

y = -$\frac{3}{4}$x + $\frac{7}{4}$

So from this, we can see that the m is -3/4, so the slope of the line would be -3/4.

There are two steps to solving the second question.

First of all, you'd need to know the slope of the line perpendicular to that of the one we just found. The product of the slopes of two perpendicular lines is -1, so

Let m be the slope of the line we're trying to find here.

The product of -3/4 and m would be -1.

-3/4 × m = -1

m = 4/3

So the slope of our line would be 4/3. So now we know that the equation of this line is y = $\frac{4}{3}$ y + C.

Now, we have to find what C is. The question gives us a point that is on this line--that is, the intersection point between x-y+2=0 and 3x+y-10=0.

Solving simultaneous equations:

$\left \{ {{x-y+2=0.......[1]} \atop {3x+y-10=0.....[2]}} \right.$

[1] + [2] : x-y+2+3x+y-10 = 0+0

4x-8 = 0 -> x = 2

Plug in 2 as x in [1]:

2-y+2=0 -> y = 4

The two lines thus intersect at (2,4).

So now we'd have to find a line y=$\frac{4}{3}$x+C that goes through (2,4).

We plug in 2 and 4 into x and y respectively:

4 = $\frac{4}{3}$×2+C

4 = $\frac{8}{3}$+C

C = 4/3

So the equation for your line would be y = 4/3x+4/3.

If you have to switch it back into standard form x+y+C=0 then just move y over to get 0 = $\frac{4}{3}$x-y+$\frac{4}{3}$.

Hope this helps, and good luck with your exam tomorrow!

Feel free to ask me any questions :)